by Elvis 16 hours 38 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Playoff Scenarios: AZ Eliminated POST #101 TOPIC AUTHOR actionjack liked this post max wrote:Good point. I didn't realize they were gonna have Saturday games.If Denver, Miami, and GB win this week, then we don't clinch.And then I bet they move us to Saturday.And if week 18's game is for the division regardless of SOV, could end up on Sunday Night Football.Personally i'm rooting for a nice meaningless Sunday afternoon game... RFU Season Ticket Holder 1 by max 15 hours 40 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #102 Elvis wrote:And if week 18's game is for the division regardless of SOV, could end up on Sunday Night Football.Personally i'm rooting for a nice meaningless Sunday afternoon game...If both SEA and Rams lose week 17, the Rams will lose the tiebreaker to SEA if AZ beats SF in week 18. I'm not sure how else SoV gets eliminated as the primary tiebreaker option. And if thats the case I'm not rooting for week 18 being for the division on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by Elvis 15 hours 22 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Playoff Scenarios: AZ Eliminated POST #103 TOPIC AUTHOR actionjack liked this post max wrote:If both SEA and Rams lose week 17, the Rams will lose the tiebreaker to SEA if AZ beats SF in week 18. I'm not sure how else SoV gets eliminated as the primary tiebreaker option. And if thats the case I'm not rooting for week 18 being for the division on SNF.If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter. RFU Season Ticket Holder 1 by actionjack 14 hours 50 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #104 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.This!!! Fuk the Niners and Block Purdy by max 14 hours 8 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #105 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.True. But I’m not gonna root for them both to lose just to have week 18 be for the division. That’s what I meant. I hate the idea of getting swept by AZ. So how else can we play for the division in week 18 if we beat AZ? I don’t see one. Which means I don’t want to be on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024 FOLLOW US @RAMSFANSUNITED Who liked this post
by max 15 hours 40 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #102 Elvis wrote:And if week 18's game is for the division regardless of SOV, could end up on Sunday Night Football.Personally i'm rooting for a nice meaningless Sunday afternoon game...If both SEA and Rams lose week 17, the Rams will lose the tiebreaker to SEA if AZ beats SF in week 18. I'm not sure how else SoV gets eliminated as the primary tiebreaker option. And if thats the case I'm not rooting for week 18 being for the division on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by Elvis 15 hours 22 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Playoff Scenarios: AZ Eliminated POST #103 TOPIC AUTHOR actionjack liked this post max wrote:If both SEA and Rams lose week 17, the Rams will lose the tiebreaker to SEA if AZ beats SF in week 18. I'm not sure how else SoV gets eliminated as the primary tiebreaker option. And if thats the case I'm not rooting for week 18 being for the division on SNF.If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter. RFU Season Ticket Holder 1 by actionjack 14 hours 50 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #104 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.This!!! Fuk the Niners and Block Purdy by max 14 hours 8 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #105 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.True. But I’m not gonna root for them both to lose just to have week 18 be for the division. That’s what I meant. I hate the idea of getting swept by AZ. So how else can we play for the division in week 18 if we beat AZ? I don’t see one. Which means I don’t want to be on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024 FOLLOW US @RAMSFANSUNITED Who liked this post
by Elvis 15 hours 22 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Playoff Scenarios: AZ Eliminated POST #103 TOPIC AUTHOR actionjack liked this post max wrote:If both SEA and Rams lose week 17, the Rams will lose the tiebreaker to SEA if AZ beats SF in week 18. I'm not sure how else SoV gets eliminated as the primary tiebreaker option. And if thats the case I'm not rooting for week 18 being for the division on SNF.If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter. RFU Season Ticket Holder 1 by actionjack 14 hours 50 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #104 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.This!!! Fuk the Niners and Block Purdy by max 14 hours 8 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #105 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.True. But I’m not gonna root for them both to lose just to have week 18 be for the division. That’s what I meant. I hate the idea of getting swept by AZ. So how else can we play for the division in week 18 if we beat AZ? I don’t see one. Which means I don’t want to be on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024 FOLLOW US @RAMSFANSUNITED Who liked this post
by actionjack 14 hours 50 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #104 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.This!!! Fuk the Niners and Block Purdy by max 14 hours 8 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #105 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.True. But I’m not gonna root for them both to lose just to have week 18 be for the division. That’s what I meant. I hate the idea of getting swept by AZ. So how else can we play for the division in week 18 if we beat AZ? I don’t see one. Which means I don’t want to be on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024
by max 14 hours 8 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #105 Elvis wrote:If they both lose this week, week 18 would be for the division.Rams win, the have the better record. Seattle wins, they win based on division record.If Seattle loses tonight, SOV no longer matters in any scenario. Both teams have to win this week for SOV to matter.True. But I’m not gonna root for them both to lose just to have week 18 be for the division. That’s what I meant. I hate the idea of getting swept by AZ. So how else can we play for the division in week 18 if we beat AZ? I don’t see one. Which means I don’t want to be on SNF. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024
by actionjack 10 hours 3 minutes ago Total posts: 4596 Joined: May 19 2016 Sactown Superstar Playoff Scenarios: AZ Eliminated POST #106 Just have to beat the cardinals Fuk the Niners and Block Purdy by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024
by Elvis 9 hours 51 minutes ago Total posts: 40130 Joined: Mar 28 2015 Los Angeles Administrator Re: Playoff Scenarios: AZ Eliminated POST #107 TOPIC AUTHOR That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version: RFU Season Ticket Holder by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024
by max 1 hour 22 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #108 Last edited by max on Dec 27 2024, edited 1 time in total. Elvis wrote:That graphic is slightly off, Rams only need 4 points. Here's the updated and corrected version:Seems like SEA needs only 13 points not 14. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business 109 posts Dec 27 2024
by max 1 hour 15 minutes ago Total posts: 5638 Joined: Jun 01 2015 Sarasota, FL Hall of Fame Playoff Scenarios: AZ Eliminated POST #109 So here's some funky math just for fun...We can use the binomial probability formula to calculate the probability that we get at least 4 wins out of 6 games. Let's start by assuming the average success rate of each of the 6 games going our way is 50-50 or 0.5. Then:The binomial probability formula: P(k; n, p) = (n choose k) * p^k * (1-p)^(n-k)where P(k; n, p) is the probability of getting exactly k successes in n trials, p is the success probability for each trial, and (n choose k) is the binomial coefficient.Exactly 4 winsTo find the probability of getting exactly 4 wins in 6 games (i), we take n=6, k=4, and, p=0.5: P(4; 6, 0.5) = (6 choose 4) * 0.5^4 * 0.5^(6-4) = 15 * 0.5^6 = 15/64At Least 4 winsFor at least 4 wins, we need to calculate the probabilities for getting 4, 5, and 6 wins and sum them up.P(4 wins) = 15/64 (as calculated above)P(5 wins) = (6 choose 5) * 0.5^5 * 0.5^(6-5) = 6 * 0.5^6 = 6/64P(6 wins) = (6 choose 6) * 0.5^6 * 0.5^(6-6) = 1 * 0.5^6 = 1/64Adding these probabilities gives us the probability of getting at least 4 wins: P(at least 4 wins) = P(4 wins) + P(5 wins) + P(6 wins) = (15+6+1)/64 = 22/64 = 11/32 =0.34But if you think it’s more likely greater than 0.5 that the average of all 6 games goes our way then substitute a higher value for p in the equations above.For example, if you use 0.6 instead of 0.5, meaning you think the average success rate of the 6 games is 60-40, which I think is a best case value, then the probability jumps to 0.54.Takeaway here is that at best it's 50-50 that we clinch in week 17. ~ max ~“The consciousness of good intentions disdains ambiguity.” - Alexander Hamilton, The Federalist Papers Reply 11 / 11 1 11 Display: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by: AuthorPost timeSubject Sort by: AscendingDescending Jump to: Forum Rams/NFL Other Sports Rams Fans United Q&A's Board Business